Instantaneous centre of rotation — the method behind AISC Manual Tables 7-6 to 7-13
and 8-4 to 8-11, solved for the geometry you actually have instead of interpolated off a printed grid.
Load–deformation from Manual Eq. 7-1 (bolts) and Eqs. 8-3 to 8-7 (welds).
Given eccentric shear in the plane of the faying surface — Manual Part 7
Bolt group
low→bolt force, fraction of rninstantaneous centreapplied Pr
Available strength
Solution
Coefficient C — Manual Table 7-6 arrangement
Bolt by bolt
Given eccentric shear on a fillet weld group — Manual Part 8
Weld group
low→segment force, fraction of peakinstantaneous centreapplied Pr
Available strength
Solution
Coefficient C — Manual Table 8-4 arrangement
How this is worked out
Both groups rotate about a point, not a centroid. An eccentric load is a rotation plus a
translation, and the two combine into pure rotation about the instantaneous centre. Where that
point sits depends on the geometry and on where and how the load is applied, so it has to be
solved for, not looked up.Manual pp. 7-7, 8-13
Deformation is proportional to distance from that centre. The element furthest from the IC is
taken to its rupture deformation; every other element gets a share in proportion to its own distance, and
its force follows from the load–deformation curve at that deformation.
Bolts follow R = Rult(1 − e−10Δ)0.55
calibrated on \xbe-in. Grade A325 bolts in double shear, with Δmax = 0.34 in.
Eq. 7-1
Welds follow Fnwi = 0.60FEXX(1.0 + 0.50 sin1.5θi)[pi(1.9 − 0.9pi)]0.3
where a weld element's strength depends on the angle its force makes with its own axis — a transverse
fillet is half again as strong as a longitudinal one, but it also ruptures at roughly a third of the
deformation, which is exactly why the two cannot both be counted at peak.
Eqs. 8-3 to 8-7
Equilibrium closes it. The IC is moved until the element forces balance the applied load in both
directions and in moment. The coefficient is then C = Rn/rn
for bolts and Rn = C C1Dl for welds — the same
numbers the Manual prints.
Concentric load is a special case. With the load through the centroid the IC is at infinity and
the group simply translates, so Specification Section J2.4 governs the weld group directly: J2.4(a) where
every element makes the same angle with the load, and the greater of Eqs. J2-10a and J2-10b where the
group has both longitudinal and transverse elements.